CLASS 10D SCIENCE

CLASS 10 SCIENCE HOLIDAY HOMEWORK WEEK 1        A)                  PORTFOLIO Prepare an Equation Bank for different types of reactions highlighting change in state, temperature, colour, precipitate formation and evolution of gas (if any). All equations must be balanced. INSTRUCTIONS:     1. All equations to be written on ruled sheets and make a folder of it.      2. Choose any 25 equations from chemistry portion of NCERT only.     WEEK 2 PRACTICAL WORK  (in practical file) AIM:   To prepare a temporary mount of a leaf peel in order to show the stomata        of a leaf INSTRUCTIONS: 1.    Copy the aim, materials required, procedure, observations, conclusions and precautions (everything on ruled side) 2.    Draw diagrams b and c given on pa...

ELECTRICITY - LESSON 3 ELECTRICITY Good morning , It is a pleasure to know that you all are logging in and doing your work Today we will make an effort to -- Evolve Ohm's Law and express it mathematically. Verify Ohm's Law experimentally. Develop meaning of resistance using Ohm's Law. List the factors which affect resistance. Explain resistivity, conductors, resistors and insulators. Experimentally determine the factors affecting resistance. But first of all let us try to a nswer yesterday's uestion : The amount off charge moved  = 5 C. Thus, the potential difference = V2-V1 = 230-240 = 10 V Therefore, Work done = Potential difference * Charge moved. That is, 10 * 5 = 50 Joules. Hence, the  work done in moving a charge of 5 coulombs from a point at 230 volts to another point at 240  volts is 50 J. A German physicist found the relationship between the current I, flowing in a wire and the potential difference across i...

Electricity Utilize your second period in completing the previous work Good morning students Today we will make an effort to -- Develop meaning of potential difference and its unit Continuing with what was given as Home Assignment Current I = 10 A Time = 2 minutes = 2 × 60 = 120 sec (a) Then charge Q = I × t = 10 × 120 = 1200 C (b) Number of electrons = 1200 C x 1/ 1.6×10 − 19                                                 = 7.5 x 10 − 17 Let us begin today's lesson The  electric charge  is equal to the number of electrons in it  and the magnitude of charge on the electron i.e. Q  = ne where n = number of electrons and e = charge of electron which is =  1.6 x  10 - 19  C            Q.  Calculate number of electrons in 1C of charge A...